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## Homework Statement

Two 2.04 µC point charges are located on the x axis. One is at x = 1.02 m, and the other is at x = -1.02 m. Determine the electric field on the y axis at y = 0.470 m.

## Homework Equations

E = k*q/r^2

## The Attempt at a Solution

First I find the distance from one of the charges to the point on the y-axis.

[tex]\sqrt(1.02^2 + 0.47^2) = 1.123m[/tex]

I also find the angle between this line and the y-axis.

[tex] tan^1 \frac{1.02}{0.47} = 65.26[/tex]

Then I found the component of the electric field at the point on the axis which lies along the y-axis.

[tex] E = k_e*\frac{q}{r^2} [/tex]

[tex] E = 8.99e9 * \frac{2.04\mu C}{1.123m}*cos(65.26) [/tex]

As this only accounts for one charge, and the other charge is equal in magnitude and position, I double this number to get the answer.

Howerver, this gives me the wrong answer. Any help would be appreciated.