### Create an Account

Home / Questions / Figure 4A6 illustrates a vapor separator that is part of a typical refrigeration system Sa...

# Figure 4A6 illustrates a vapor separator that is part of a typical refrigeration system Saturated liquid R134a leaves the condenser at state 1 with mass flow rate mcond

Figure 4.A-6 illustrates a vapor separator that is part of a typical refrigeration system. Saturated liquid R134a leaves the condenser at state 1 with mass flow rate mcond ? = 0.05 kg/s and pressure Pcond = 890 kPa. This refrigerant enters the vapor separator (a large, insulated tank) through a valve (shown in fig.). At the exit of the valve (state 2), the vapor is in two-phase condition. The pressure in the tank is Ptank = 500 kPa. There is no pressure drop due to flow through the tank (i.e., the pressure at states 2, 3, and 5 are all the same). The liquid portion of this flow falls to the bottom of the tank due to gravity while the vapor portion remains at the top. Saturated liquid is drawn from the bottom of the tank (at state 3) and expands through a valve to state 4 where it enters the evaporator at Pevap = 120 kPa. The saturated vapor is drawn off of the top of the tank at state 5 and fed to a compressor. Assume that the vapor separator is adiabatic, rigid, and operating at steady state.

a.) Determine the quality of the refrigerant at state 2.

b.) Determine the mass flow rate of refrigerant that goes to the evaporator ( mevap ) and the mass flow rate of refrigerant that goes to the compressor (mcomp).

c.) Generate a temperature-specific volume (T-v) diagram. Overlay the state points indicated in Figure 4.A-6 onto this diagram. Number the states.

Show transcribed image text Figure 4.A-6 illustrates a vapor separator that is part of a typical refrigeration system. Saturated liquid R134a leaves the condenser at state 1 with mass flow rate mcond ? = 0.05 kg/s and pressure Pcond = 890 kPa. This refrigerant enters the vapor separator (a large, insulated tank) through a valve (shown in fig.). At the exit of the valve (state 2), the vapor is in two-phase condition. The pressure in the tank is Ptank = 500 kPa. There is no pressure drop due to flow through the tank (i.e., the pressure at states 2, 3, and 5 are all the same). The liquid portion of this flow falls to the bottom of the tank due to gravity while the vapor portion remains at the top. Saturated liquid is drawn from the bottom of the tank (at state 3) and expands through a valve to state 4 where it enters the evaporator at Pevap = 120 kPa. The saturated vapor is drawn off of the top of the tank at state 5 and fed to a compressor. Assume that the vapor separator is adiabatic, rigid, and operating at steady state. a.) Determine the quality of the refrigerant at state 2. b.) Determine the mass flow rate of refrigerant that goes to the evaporator ( mevap ) and the mass flow rate of refrigerant that goes to the compressor (mcomp). c.) Generate a temperature-specific volume (T-v) diagram. Overlay the state points indicated in Figure 4.A-6 onto this diagram. Number the states.

Jun 24 2020 View more View Less