### Video Transcript

List the coordinates of the
π₯-intercept and the π¦-intercept of the line π₯ over three minus π¦ over two is
equal to one.

Now, looking carefully at the form
in which the equation of this line has been given, we should notice that it looks
very similar to the two-intercept form of the equation of a straight line. The two-intercept form is π₯ over
π plus π¦ over π equals one, where the line intercepts the π₯-axis at π, zero and
intercepts the π¦-axis at zero, π. However, if we look really closely
at this equation, we see that there is a subtraction sign rather than an addition
sign between the two terms on the left-hand side. We therefore need to manipulate the
equation weβve been given so that it matches up fully with the two-intercept
form. And weβll then be able to use it to
determine the coordinates of the π₯- and π¦-intercepts.

From our knowledge of algebra, we
know that subtracting π¦ over two is the same as adding negative π¦ over two or we
can think of this as adding π¦ over negative two. It doesnβt matter whether we write
that negative in the numerator or denominator of the quotient. So we can take this equation π₯
over three minus π¦ over two equals one and rewrite it as π₯ over three plus π¦ over
negative two equals one. The only change is in that second
term. Now we wouldnβt usually choose to
leave a negative value in the denominator of a quotient like this. But by doing this, our equation now
matches up exactly with the format of the two-intercept form of the equation of a
straight line.

We can therefore determine the π₯-
and π¦-intercepts by considering the denominators of the two quotients. The denominator for the π₯-term is
three, which tells us that the value of π is three, and so the coordinates of the
π₯-intercept are three, zero. Looking at the second term, we see
that the denominator for π¦ is negative two. This tells us then that the value
of π is negative two, and so the coordinates of the π¦-intercept are zero, negative
two. By manipulating the equation we
were given slightly so that it perfectly matches up with the two-intercept form of
the equation of a straight line, we found that the coordinates of the π₯-intercept
of this line are three, zero and the coordinates of the π¦-intercept are zero,
negative two.