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Consider the basic uplink AWGN channel in 61 with power constraints Pk on user k for

Consider the basic uplink AWGN channel in (6.1) with power constraints Pon user (for = 12). In Section 6.1.3, we stated that orthogonal multiple access is optimal when the degrees of freedom are split in direct proportion to the powers  of

the users. Verify this. Show also that any other split of degrees of freedom is strictly suboptimal, i.e., the corresponding rate pair lies strictly inside the capacity region given by the pentagon in Figure 6.2. Hint: Think of the sum rate as the performance of a point-to-point channel and apply the insight from Exercise  5.6.

 

 

 

Jul 31 2020 View more View Less

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