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Consider an object cooled by the evaporation of liquid nitrogen at its normal boiling point 7734K What volume of gas at 100 atm must be produced to remove 48 21 kJ of heat energy from the object

Consider an object cooled by the evaporation of liquid nitrogen at its normal boiling point (77.34K). What volume of gas at 1.00 atm must be produced to remove 48.21 kJ of heat energy from the object?
 

Jul 23 2020 View more View Less

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