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A survey of 1000 air travelers1 found that 60 % prefer a window seat The sample size is large enough to use the normal distribution and a bootstrap distribution shows that the standard error is

A survey of 1000 air travelers1 found that 60 % prefer a window seat. The sample size is large enough to use the normal distribution, and a bootstrap distribution shows that the standard error is StartItalic UpperWord SE EndItalic equals 0.015. Use a normal distribution to find a 95 % confidence interval for the proportion of air travelers who prefer a window seat. Round your answers to three decimal places. The 95 % confidence interval is

Apr 05 2020 Read more Less More

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