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# A five-sided closed field traverse has the following distances in meters AB 5766 BC The adjusted angles are as follows

 A five-sided closed field traverse has the following distances in meters: AB = 51.766; BC = 26.947; CD = 37.070; DE = 35.292; EA = 19.192. The adjusted angles are as follows: A = 101°03′19″; B = 101°41′49″; C = 102°22′03″; D = 115°57′20″; E = 118°55′29″. The bearing of AB is N 73°00′00″ E. BC is in the S.E. quadrant.The coordinates of the five(5) corners of the traverse have been computed to be as follows: Corner "A" X Coordinate 1000.000 Y Coordinate 1000.000 Corner "B" X Coordinate 1050.019 Y Coordinate 1013.314 Corner "C" X Coordinate 1062.085 Y Coordinate 989.218 Corner "D" X Coordinate 1033.262 Y Coordinate 965.900 Corner "E" X Coordinate 1001.292 Y Coordinate 980.852 The area of the traverse using the coordinate method is 1,857 Square meters. If you used the area computation method we used in class and on the homeworks, the computed number using coordinate method for area computation for corner "C" is_______? Your answer will be in square meters to four (4) decimal place accuracy.

Apr 27 2020 View more View Less Subscribe To Get Solution