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a Derive an expression for calculating the effectiveness of a parallel flow heat exchanger b A parallel flow heat exchanger has to cool 2500 kg hr of oil from 70oC to 30oC Cooling water enters

a) Derive an expression for calculating the effectiveness of a parallel flow heat exchanger.

(b) A parallel flow heat exchanger has to cool 2500 kg/hr of oil from 70oC to 30oC. Cooling water enters the exchanger at 10oC and leaves at 20oC. Specific heat of oil is 2.1 kJ/kg.K. Determine the effectiveness of the heat exchanger and heat transfer capacity.

 

Jul 24 2020 View more View Less

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