Home / Questions / a Derive an expression for calculating the effectiveness of a parallel flow heat exchanger...
(b) A parallel flow heat exchanger has to cool 2500 kg/hr of oil from 70^{o}C to 30^{o}C. Cooling water enters the exchanger at 10^{o}C and leaves at 20^{o}C. Specific heat of oil is 2.1 kJ/kg.K. Determine the effectiveness of the heat exchanger and heat transfer capacity.
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