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A 1000W electric motor is connected to a source of 120 Vms 60 Hz and the result is a lagging pf of 08 To correct the pf to 095 lagging a capacitor is placed in parallel with the motor

A 1,000-W electric motor is connected to a source of 120 Vms, 60 Hz, and the result is a lagging pf of 0.8. To correct the pf to 0.95 lagging, a capacitor is placed in parallel with the motor. Calculate the current drawn from the source with and without the capacitor connected. Determine the value of the capacitor required to make the correction.

7.21      The motor inside a blender can be modeled as a resistance in series with an inductance, as shown in Figure P7.21.

a.    What is the average power, PAV, dissipated in the load?

b.    What is the motor’s power factor?

c.    What value of capacitor when placed in parallel with the motor will change the power factor to 0.9 (lagging)?

Jun 18 2020 View more View Less

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