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The pH of one cubic meter (1 m2) groundwater is 9, and its pH will be decreased from 9 to 7 using sodium-dihydrogen phosphate (NaH2PO4) salt. Sodium dihydrogen phosphate is very soluble in water and quickly dissociates to sodium (Na+) and dihydrogen phosphate (H2PO4') ions as shown by the following reaction: NaH2PO4(s) → Na* + H2PO4 Then, H2PO4 donates only one proton (H) between pH 7 and 9: H2PO4 + H+ + HPO 2 Neglect ionic strength effects and use the information given in problem, calculate how many milligrams (mg) of sodium dihydrogen phosphate salt (NaH2PO4) should be added into 1 m3 of groundwater to decrease the pH from 9 to 7. Molecular weights (g/mole): Na = 23; H = 1; P = 31; 0 = 16
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