Create an Account

Already have account?

Forgot Your Password ?

Home / Questions / Show that at most one node in an AVL tree becomes temporarily unbalanced after the immedia...

Show that at most one node in an AVL tree becomes temporarily unbalanced after the immediate deletion of a node as part of the standard remove map operation 2 In our AVL implementation each node

Show that at most one node in an AVL tree becomes temporarily unbalanced after the immediate deletion of a node as part of the standard remove map operation.

2. In our AVL implementation, each node stores the height of its subtree, which is an arbitrarily large integer. The space usage for an AVL tree can be reduced by instead storing the balance factor of a node, which is defined as the height of its left subtree minus the height of its right subtree. Thus, the balance factor of a node is always equal to −1, 0, or 1, except during an insertion or removal, when it may become temporarily equal to −2 or +2. Reimplement the AVLTreeMap class storing balance factors rather than subtree heights.

Jun 11 2020 View more View Less

Answer (Solved)

question Subscribe To Get Solution

Related Questions