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In Example 7.3 we saw that the probability of 10 arrivals in two hours is not double the probability of 5 arrivals in one hour; in fact, it is less than the probability of 5 arrivals in one hour. Explain why this is the case.
Example 7.3
Suppose customers arrive to a 7–11 convenience store according to a Poisson process with rate 10 per hour. What are the probabilities of (a) no customers in an hour; (b) exactly 5 customers in an hour; (c) exactly 10 customers in two hours; and (d) at least two customers in half an hour?
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