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Home / Questions / Boron trifluoride, BF3, and diethyl ether, (C2H5)2O, react to produce a compound with the ...

Boron trifluoride, BF3, and diethyl ether, (C2H5)2O, react to produce a compound with the formula BF3:(C2H5)2O. A coordinate covalent bond is formed between the boron atom on BF3 and the oxygen atom o

Boron trifluoride, BF3, and diethyl ether, (C2H5)2O, react to produce a compound with the formula BF3:(C2H5)2O. A coordinate covalent bond is formed between the boron atom on BF3 and the oxygen atom on (C2H5)2O. Write the equation for this reaction, using Lewis electron-dot formulas. Label the lewis acid and the Lewis base. Determine how many grams of BF3:(C2H5)2O are formed when 9.10g BFand 23.3g (C2H5)2O are placed in a reaction vessel, assuming that the reaction goes to completion. 

Jun 30 2021 View more View Less

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